Practicing Success
Practicing Success
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The value of $sin(2sin^{-1}\frac{4}{5})$ is given by : |
$\frac{16}{25}$ $\frac{24}{25}$ $\frac{9}{25}$ $\frac{12}{25}$ |
$\frac{24}{25}$ |
The correct answer is Option (2) → $\frac{24}{25}$ $\sin(2\sin^{-1}\frac{4}{5})$ let $θ=\sin^{-1}\frac{4}{5}$ $\sin θ=\frac{4}{5}$ so $\cos θ=\frac{3}{5}$ $\sin(2θ)=2\sin θ\cos θ$ $⇒2×\frac{4×3}{5×5}=\frac{24}{25}$ |
