Two objects of mass 10 kg and 20 kg respectively are connected to the two ends of a rigid rod of length 10 m with negligible mass. The distance of the center of mass of the system from the 10 kg mass is :

\(\frac{10}{3}\) m \(\frac{20}{3}\) m 10 m 5 m

\(\frac{20}{3}\) m

Xcm = \(\frac{m_1 x_1 + m_2 x_2}{m_1 + m_2}\) m1 = 10 Kg ; m2 = 20 Kg ; x1 = 0 m ; x2 = 10 m Xcm = \(\frac{20}{3}\) m