Abhishek climbs up a hill at a speed of 3 mi/h and comes down at a speed of 5 mi/h. If the total time taken for the two-way journey is 10 hours, then what is the distance between the hilltop and the foothill ?

18.75 mi

Let distance b/w foothill and to = D miles

According to question ,

\(\frac{D}{3}\) + \(\frac{D}{5}\)  = 10 hours

\(\frac{8D}{15}\) = 10

8D = 150m

D = \(\frac{150}{8}\) 

= 18.75 miles

So , Distance b/w foothill and top is 18.75 ml/h