In a hydrogen atom, an electron is moving in the nth permitted orbit of radius $r_n$. The wavelength associated with this electron is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{2πr_n}{n}$
According to De-Broglie's hypothesis, the wavelength (λ) associated with particle -
$λ=\frac{h}{P}$ [P = momentum]
and,
Bohr model state that the,
$L=nh$
[n = quantum number]
∴ Momentum, $P=\frac{L}{r}=\frac{nh}{r}$
$∴λ=\frac{h}{\frac{nh}{r}}=\frac{2\pi r}{n}$
Now,
$r_n=n^2.r_1$
$∴λ_n=\frac{2πr_n}{n}$