Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

A diode having potential difference 0.5 V across its junction which does not depend on current, is connected in series with resistance of 20Ω across source. If 0.1 A current passes through resistance then what is the voltage of the source?

Options:

1.5 V

2.0 V

2.5 V

5 V

Correct Answer:

2.5 V

Explanation:

$V' = V + IR = 0.5 + 0.1× 20 = 2.5V$