CUET Preparation Today
The function $f(x)=\left\{\begin{array}{cl}\frac{x^2+2 x-3}{x-1} & , \text { if } x \neq 1 \\ 0 & , \text { if } x=1\end{array}\right.$ is |
Continuous at x = 1 discontinuous at x = 1 Continuous at each real number discontinuous at each real number |
discontinuous at x = 1 |
The correct answer is Option (2) - discontinuous at x = 1 $f(1)=0$ $\lim\limits_{x→1}\frac{x^2+2x-3}{x-1}=\lim\limits_{x→1}\frac{(x-1)(x+3)}{(x-1)}$ $\lim\limits_{x→1}(x+3)=4$ $4≠0$ at x = 1 f(x) is discontinuous |
