A and B start moving from places X to Y and Y to X respectively, at the same time on the same day.  After crossing each other, A and B takes 20\(\frac{1}{4}\) hours and 16 hours, respectively, to reach the respective destinations.  If the speed of A is 32 Km/h, then the speed (in km/h) of B is?

36

We have direct result:

\(\sqrt {\frac{T_2}{T_1}}\) = \(\frac{S_1}{S_2}\)

⇒ \(\sqrt {\frac{16}{\frac{81}{4}}}\) = \(\frac{32}{S_2}\)

⇒S₂ = \(\frac{32 × 9}{8}\) = 36 km/h