Find the area bounded by the curves y = x2 and $y=\frac{2}{1+x^2}$.

$π$ $π-\frac{1}{3}$ $π-\frac{2}{3}$ $π-\frac{1}{4}$

$π-\frac{2}{3}$

Shaded Area = $2\int\limits_0^A(\frac{2}{1+x^2}-x^2)dx$ Solve $y=\frac{2}{1+x^2}$ and y = x2, A ≡ (1,1) ⇒ Shaded Area = $2\int\limits_0^1(\frac{2}{1+x^2}-x^2)dx=π-\frac{2}{3}$