Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The velocity v of a particle at time t is given by v = at + b/(t + c), where a, b and c are constants, The dimensions of a, b and c are respectively :

Options:

[LT-2], [L] and [T]

[L], [T] and [LT2]

[L2T2], [LT] and [L]

[L], [LT] and [T2]

Correct Answer:

[LT-2], [L] and [T]

Explanation:

\(v = at + \frac{b}{t + c}\)

⇒ [c] [t] = T

[v] = [at] ⇒ [a] = \(\frac{[v]}{[t]}\) = LT –2

[b] = [LT–1] T = L