CUET Preparation Today
Differentiate the function $e^{\cos x}$ with respect to $x$. |
$e^{\cos x}$ $\sin x \cdot e^{\cos x}$ $-\sin x \cdot e^{\cos x}$ $-\cos x \cdot e^{\sin x}$ |
$-\sin x \cdot e^{\cos x}$ |
The correct answer is Option (3) → $-\sin x \cdot e^{\cos x}$ ## Let $y = e^{\cos x}$. Using chain rule, we have $\frac{dy}{dx} = e^{\cos x} \cdot (-\sin x) = -(\sin x)e^{\cos x}$ |
