The direction cosines of a vector equally inclined to the axes \(OX,OY\) and \(OZ\) are
Answer & explanation
Correct answer: option 2
\(\begin{aligned}l=\cos \alpha, m=\cos \alpha, n&=\cos \alpha\\ \text{Since }l^{2}+m^{2}+n^{2}&=1\\ 3\cos^{2}\alpha&=1\\ \cos^{2}\alpha &=\frac{1}{3}\\ \cos \alpha &=\pm \frac{1}{\sqrt{3}}\end{aligned}\)