The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.

The average of marks obtained by S3 and S5 is what percent less than the marks obtained by S9?

7%

Average marks of S3 & S5 = \(\frac{87 + 99}{2}\)

= \(\frac{186}{2}\)

= 93

Marks obtained by S9 = 100

Required percentage = = \(\frac{100 - 93 }{100}\) × 100

= 7%