The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.
The average of marks obtained by S3 and S5 is what percent less than the marks obtained by S9?
Answer & explanation
Correct answer: option 1
Average marks of S3 & S5 = \(\frac{87 + 99}{2}\)
= \(\frac{186}{2}\)
= 93
Marks obtained by S9 = 100
Required percentage = = \(\frac{100 - 93 }{100}\) × 100
= 7%