The reverse bias in a junction diode is changed from 5V to 15V then the value of current changes from 38μA to 88μA. The resistance of junction diode will be:
Answer & explanation
Correct answer: option 3
$r_r=\frac{V_{r_2}-V_{r_1}}{I_{r_2}-V_{I_1}}=\frac{15-5}{(88-38)×10^{-6}}=2×10^5 Ω$