Practicing Success
Practicing Success
CUET Preparation Today
The reverse bias in a junction diode is changed from 5V to 15V then the value of current changes from 38μA to 88μA. The resistance of junction diode will be: |
$4 × 10^5 Ω$ $3× 10^5 Ω$ $2 × 10^5 Ω$ $10^6 Ω$ |
$2 × 10^5 Ω$ |
$r_r=\frac{V_{r_2}-V_{r_1}}{I_{r_2}-V_{I_1}}=\frac{15-5}{(88-38)×10^{-6}}=2×10^5 Ω$ |
