Practicing Success
A particle is launched from the surface of earth with speed v. For the particle to move as a satellite, which statement is correct? |
$\frac{v_{e}}{2} < v < v_{e}$ $\frac{v_{e}}{\sqrt{2}} < v < v_{e}$ $v_{e} < v <\sqrt{2 v_{e}}$ $\frac{v_{e}}{\sqrt{2}} < v < \frac{v_{e}}{2}$ |
$\frac{v_{e}}{\sqrt{2}} < v < v_{e}$ |
$v_e=\sqrt{\frac{2 G m}{r}}, \quad v_0=\sqrt{\frac{G m}{r}}$, we have $v_0<v<v_{e}$ $\Rightarrow \frac{v_{e}}{\sqrt{2}}<v<v_{e}$ $\left\{∵ v_0=\sqrt{\frac{GM}{r}} ~\text{and}~ v_{e}=\sqrt{\frac{2 GM}{r}}\right\}$ |