$tan(θ - 14π)$ is equal to:
Answer & explanation
Correct answer: option 1
tan ( θ - 14Π )
= tan( - ( 14Π - θ ) )
= - tan ( 14Π - θ )
= - tan ( 2 × 7Π - θ )
We know , tan(2 × nΠ - θ ) = - tanθ
= - ( - tanθ )
= tanθ
$tan(θ - 14π)$ is equal to:
Correct answer: option 1
tan ( θ - 14Π )
= tan( - ( 14Π - θ ) )
= - tan ( 14Π - θ )
= - tan ( 2 × 7Π - θ )
We know , tan(2 × nΠ - θ ) = - tanθ
= - ( - tanθ )
= tanθ