Find the value of \(\frac{cos^234°\;+\;cos^256°}{sin^230°}\)

2 0 4 3

4

Formula → [cos2A + cos2B = 1, when A + B = 90°] Here, (34° + 56° = 90°), therefore, ⇒ \(\frac{cos^234°\;+\;cos^256°}{sin^230°}\) = 4 × \(\frac{1}{1}\)  = 4