Practicing Success
The coefficient of performance of a refrigerator is 11. If the temperature inside freezer is –35°C, the temperature of the surroundings to which it rejects heat is : |
245 K 255 K 260 K 278 K |
260 K |
$COP(\kappa) = \frac{1}{\frac{T_1}{T_2} - 1}= \frac{ T_2}{T_1 - T_2}$ k = 11 ; T2 = - 35°C = 238 K $ T_1 - T_2 = \frac{T_2}{\kappa} = \frac{238}{11} = 21.6$ $\Rightarrow T_1 = 238+ 21.6 = 259.6K = 260 K$ |