Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Thermodynamics

Question:

The coefficient of performance of a refrigerator is 11. If the temperature inside freezer is –35°C, the temperature of the surroundings to which it rejects heat is : 

Options:

245 K

255 K

260 K

278 K

Correct Answer:

260 K

Explanation:

$COP(\kappa) = \frac{1}{\frac{T_1}{T_2} - 1}= \frac{ T_2}{T_1 - T_2}$

k = 11 ; T2 = - 35°C = 238 K

$ T_1 - T_2 = \frac{T_2}{\kappa} = \frac{238}{11} = 21.6$

$\Rightarrow T_1 = 238+ 21.6 = 259.6K = 260 K$