If cosecθ = 1.25
find the value of \(\frac{4tanθ - 5cosθ+1}{secθ + 4cotθ-1}\)+\(\frac{10}{11}\).
Answer & explanation
Correct answer: option 3
cosecθ =\(\frac{125}{100}\)=\(\frac{5}{4}\)=\(\frac{H}{P}\) (Triplet 3, 4, 5)
B = 3
Put than in find
⇒ \(\frac{4×\frac{4}{3}-5×\frac{3}{5}+1}{\frac{5}{3}+4×\frac{3}{4}-1}\)+\(\frac{10}{11}\) ⇒ \(\frac{\frac{16}{6}-3+1}{\frac{5}{3}+3-4}\)+\(\frac{10}{11}\)
⇒ \(\frac{\frac{10}{3}}{\frac{11}{3}}\)+\(\frac{10}{11}\)
= \(\frac{20}{11}\)