Practicing Success
A spherical shell of radius R is carries a uniform surface charge q. Take the reference point at ∞ |
What is the potential at r<R?
|
q/4πεor q/4πεoR q/4πεo(R -r) zero |
q/4πεoR |
For r < R, it is assumed that the entire charge is concentrated at the center of the sphere. Thus, the effective distance of separation becomes = r. |