Rs.9478 is invested in two parts at the rate of 8% per annum compounded annually for 8 years and 6 years respectively. If amount received on both investments is equal, then find the difference between both investments.
Answer & explanation
Correct answer: option 2
Let amount invested for 8 years is P1 & amount invested for 6 years is P2.
ATQ,
⇒ P1 (1+ \(\frac{8}{100}\))8 = P2(1+ \(\frac{8}{100}\))6
⇒ P1 (1+ \(\frac{8}{100}\))2 = P2
⇒ P1 (\(\frac{27}{25}\))2 = P2
⇒ P1 (\(\frac{729}{625}\)) = P2
⇒ P1 : P2 = 625 : 729 → 1354 (Total)
Here,
⇒ 1354 R = 9478
⇒ 1R = 7
Hence, Difference of parts = (729 - 625)R = 104R = 104 x 7 = 728