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Find the mean, variance and standard deviation of the probability distribution:
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Mean = 3.1, Variance = 0.49, Standard deviation = 0.7 Mean = 3.1, Variance = 0.29, Standard deviation = 0.54 Mean = 3, Variance = 0.5, Standard deviation = 0.5 Mean = 3.5, Variance = 1.25, Standard deviation = 1.12 |
Mean = 3.1, Variance = 0.49, Standard deviation = 0.7 |
The correct answer is Option (1) → Mean = 3.1, Variance = 0.49, Standard deviation = 0.7 We construct the following table:
Mean = $μ = 3.1$ Variance = $Σp_i{x_i}^2- μ^2 = 10.1 - (3.1)^2 = 10.1-9.61 = 0.49$ Standard deviation = $\sqrt{0.49} = 0.7$ |
