A card from a well shuffled deck of 52 playing cards is lost. From the remaining cards of the pack, a card is drawn at random and is found to be a king. Find the probability of the lost card being a king. |
$\frac{1}{13}$ $\frac{1}{15}$ $\frac{3}{51}$ $\frac{4}{51}$ |
$\frac{3}{51}$ |
The correct answer is Option (3) → $\frac{3}{51}$ ## $E_1$: Lost card is king, $E_2$: Lost card is not king. Let $A$: a card drawn from remaining pack is king. $P(E_1) = \frac{4}{52}, P(E_2) = \frac{48}{52}$ $P\left(\frac{A}{E_1}\right) = \frac{3}{51}, P\left(\frac{A}{E_2}\right) = \frac{4}{51}$ $ P\left(\frac{E_1}{A}\right) = \frac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1) + P(E_2)P(A|E_2)}$ $ P\left(\frac{E_1}{A}\right)= \frac{\frac{4}{52} \cdot \frac{3}{51}}{\frac{4}{52} \cdot \frac{3}{51} + \frac{48}{52} \cdot \frac{4}{51}}$ $ P\left(\frac{E_1}{A}\right) = \frac{4\times 3}{4\times 3+ 48\times 4}$ $ P\left(\frac{E_1}{A}\right)= \frac{3}{51}$ |