CUET Preparation Today
Find the general solution of the differential equation $\frac{dy}{dx} = x$. |
$y = x^2 + C$ $y = \frac{x^2}{2} + C$ $y = \frac{x}{2} + C$ $y = \frac{x^3}{3} + C$ |
$y = \frac{x^2}{2} + C$ |
The correct answer is Option (2) → $y = \frac{x^2}{2} + C$ ## Separate the variables of the differential equation. $ dy = xdx $ $ \int dy = \int xdx$ $ y = \frac{x^2}{2} + c $ |
