The wavelength of matter wave for a moving charged particle is independent of
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → charge
The de Broglie wavelength of any moving particle is set by its momentum alone.
\( \displaystyle \lambda = \frac{h}{p} = \frac{h}{m v} \)
The formula contains the mass, the velocity and the momentum, but not the charge. A charged particle and a neutral particle with the same momentum have the same wavelength, so the wavelength is independent of charge.
Note: The same question was also asked in CUET (UG) 2023 on 07-06-2023 (Slot 3) and on 26-05-2023 (Slot 3).
NCERT (2026-27):
Summary – “… 9. The de Broglie wavelength (\( \lambda \)) associated with a moving particle is related to its momentum p as: \( \lambda = h/p \). The dualism of matter is inherent in the de Broglie relation which contains a wave concept (\( \lambda \)) and a particle concept (p). The de Broglie wavelength is independent of the charge and nature of the material particle.”