Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

The degree of the differential equation $y_2^{3/2}-y_1^{1/2}-4=0$ is:

Options:

6

3

2

4

Correct Answer:

6

Explanation:

$(\frac{d^2y}{dx^2})^{3/2}-(\frac{dy}{dx})^{1/2}-4=0⇒(\frac{d^2y}{dx^2})^3=16+(\frac{dy}{dx})+8(\frac{dv}{dx})^{1/2}$

$⇒[(\frac{d^2y}{dx^2})^3-16-(\frac{dy}{dx})]^2=64(\frac{dy}{dx})$

⇒ degree = 6 and order = 2