Let for all real values of x, $h(x)=f(x)-\{f(x)\}^2+\{f(x)\}^3, x ∈ R$. Then
Answer & explanation
Correct answer: option 3
We know that f is increasing or decreasing according as or < 0. Also
$h'(x)=f'(x)-2f(x)+3\{f(x)\}^2f'(x)=f'(x)[3\{f(x)\}^2-2f(x)+1]$ .....(a)
Now for $3\{f(x)\}^2-2f(x)+1, B^2-4AC=4-12=-8<0$ and $A=3>0$,
so $3\{f(x)\}^2-2f(x)+1>0∀x$
Hence $h'(x)$ is +ve or -ve according as $f'(x)>0$ or < 0
⇒ $h(x)$ is increasing when f is increasing or
⇒ $h(x)$ is decreasing when f is decreasing