Two concentric circular coils of 10 turns each are situated in the same plane. Their radii are 20 cm and 40 cm and they carry 0.2 A and 0.3 A currents respectively in opposite directions. The magnetic field at the center is |
$\frac{35}{4}μ_0T$ $\frac{1}{80}μ_0T$ $\frac{7}{80}μ_0T$ $\frac{5}{4}μ_0T$ |
$\frac{5}{4}μ_0T$ |
The correct answer is Option (4) → $\frac{5}{4}μ_0T$ Magnetic field due to a coil, $B=\frac{μ_0nI}{2r}$ for coil 1, $B_1=\frac{μ_0n_1I_1}{2r_1}=\frac{4π×10^{-7}×10×0.2}{2×0.2}$ $=2π×10^{-6}T$ for coil 2, $B_2=\frac{μ_0n_2I_2}{2r_2}=\frac{4π×10^{-7}×10×0.3}{2×0.4}$ $=1.5π×10^{-6}T$ $∴ΔB=B_1-B_2$ $=(1.5π×10^{-6}-2π×10^{-6})T$ $≃1.57×10^{-6}Wb/m^2=\frac{5}{4}μ_0T$ |