The equivalent resistance between P and Q in the figure is approximately:
Answer & explanation
Correct answer: option 2
The simple circuit is as shown below:
Rnet = $\frac{10 \times(8+24 / 7)}{10+(8+24 / 7)}$ = 5.3 Ω
The equivalent resistance between P and Q in the figure is approximately:
Correct answer: option 2
The simple circuit is as shown below:
Rnet = $\frac{10 \times(8+24 / 7)}{10+(8+24 / 7)}$ = 5.3 Ω