AB is the chord of a circle and O is the  center of a circle. ∠AOB = 130 degree. What is the angle subtended by the same chord in the major segment of the circle ?

65 degree 

Chord AB subtends \(\angle\)AOB at the center and \(\angle\)ADB at a point D of the remaining parts of a circle, therefore, \(\angle\)AOB = 2\(\angle\)ADB

= \(\angle\)ADB = \(\frac{1}{2}\)AOB = \(\frac{1}{2}\) x 130 = \({65}^\circ\).