A beam of light converges at a point M. Now a concave lens of focal length 32 cm is placed in the path of convergent beam 24 cm from M. Now the beam will converge at:

+96 cm from lens

The correct answer is Option (3) → +96 cm from lens

Object is virtual

u = 24 cm

f = – 32 cm

$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

$-\frac{1}{32}=\frac{1}{v}-\frac{1}{24}$

$\frac{1}{v}=\frac{-1}{32}+\frac{1}{24}=\frac{8}{32 \times 24}$

v = 96 cm from lens.