A beam of light converges at a point M. Now a concave lens of focal length 32 cm is placed in the path of convergent beam 24 cm from M. Now the beam will converge at:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → +96 cm from lens
Object is virtual
u = 24 cm
f = – 32 cm
$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
$-\frac{1}{32}=\frac{1}{v}-\frac{1}{24}$
$\frac{1}{v}=\frac{-1}{32}+\frac{1}{24}=\frac{8}{32 \times 24}$
v = 96 cm from lens.