Practicing Success
PAQ is a tangent to circle with centre O, at a point A on it. AB is a chord such that $\angle B A Q=x^{\circ}(x<90)$. C is a point on the major arc AB such that $\angle A C B=y^{\circ}$. If $\angle A B O=32^{\circ}$, then the value of x + y is: |
98 112 110 116 |
116 |
OA is radius of circle and makes 90º with tangent. ∠OAQ = 90º ∠OAQ = ∠OAB + ∠BAQ 90º = 32º + ∠BAQ { OA = OB ⇒ ∠OAB = ∠ABO } ∠BAQ = 58º By using alternate segment theorem , ∠BAQ = ∠ACB Hence , ∠ACB = 58º Now, x + y = 58º + 58º = 116º
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