If $Cos A=\frac{9}{41}$, find cotA.
Answer & explanation
Correct answer: option 1
$Cos A=\frac{9}{41}$
B = 9 & H = 41
Using pythagoras theorem ,
P2 + B2 = H2
P2 + 92 = 412
P = 40
Now , cotA = \(\frac{B}{P}\) = \(\frac{9}{40}\)
If $Cos A=\frac{9}{41}$, find cotA.
Correct answer: option 1
$Cos A=\frac{9}{41}$
B = 9 & H = 41
Using pythagoras theorem ,
P2 + B2 = H2
P2 + 92 = 412
P = 40
Now , cotA = \(\frac{B}{P}\) = \(\frac{9}{40}\)