If $Cos A=\frac{9}{41}$, find cotA.

$\frac{9}{40}$ $\frac{41}{40}$ $\frac{40}{9}$ $\frac{9}{41}$

$\frac{9}{40}$

$Cos A=\frac{9}{41}$ B = 9 & H = 41 Using pythagoras theorem , P2 + B2 = H2 P2 + 92 = 412 P = 40 Now , cotA = \(\frac{B}{P}\) = \(\frac{9}{40}\)