Find x if 2 sin2 x - 1 = 0.

$\frac{\pi}{4}$ $\frac{\pi}{2}$ 0 $\pi $

$\frac{\pi}{4}$

2 sin2 x - 1 = 0 2 sin2 x = 1 sin2 x = \(\frac{1 }{2}\) sinx = \(\frac{1 }{√2}\) { we know, sin45º = \(\frac{1 }{√2}\) } and 45º = \(\frac{π }{4}\) So, x = \(\frac{π }{4}\)