Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Options:

a

b

c

d

Correct Answer:

b

Explanation:

Fringe width $\beta = \frac{\lambda D}{d} = \frac{6.5 \times 10^{-7}}{10^{-3}} = 0.65 mm$

Distance of $5^{th}$ bright fringe from $3^{rd}$ dark fringe is $\frac{5\lambda}{2}= 1.63 mm$