In a Young's double slit experiment, angular width of a fringe formed on a distant screen is 0.1o. If wavelength of light used is 6000 Å , then distance between the slits will be
Answer & explanation
Correct answer: option 2
The correct answer is Option 2: 0.344 mm
$ \theta = \frac{\lambda}{d}$
$ d = \frac{\lambda}{\theta}$
$d = \frac{6\times 10^{-5} \times 180\times 7}{0.1\times 22} = 0.344mm$