In a Young's double slit experiment, angula width of a fringe formed on a distant screen is 0.1o. If wavelength of light used is 6000 Å , then distance between the slits will be

0.241 mm    0.344 mm   0.519 mm 0.413 mm

0.344 mm

$ \theta = \frac{\lambda}{d}$ $ d = \frac{\lambda}{\theta}$ $d = \frac{6\times 10^{-5} \times 180\times 7}{0.1\times 22} = 0.344mm$