How many of the following ions act as strong oxidising agents in aqueous solution?
Mn3+, Ti2+, Co3+, V2+, Ce4+, Cr2+, Eu2+
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 3
An ion that is easily reduced to a more stable lower state is a strong oxidising agent; an ion that is easily oxidised to a more stable higher state is a strong reducing agent.
Strong oxidising agents:
Mn3+ (reduced to Mn2+, stable half-filled d5)
Co3+ (with Mn3+, one of the two strongest oxidising 3d ions in water)
Ce4+ (reverts to the common +3 state; E° Ce4+/Ce3+ = +1.74 V)
Strong reducing agents (not counted):
Ti2+ — oxidised to Ti3+; liberates hydrogen from a dilute acid.
V2+ — oxidised to V3+.
Cr2+ — liberates hydrogen from a dilute acid:
\( \displaystyle \ce{2Cr^2+(aq) + 2H+(aq) -> 2Cr^3+(aq) + H2(g)} \)
Eu2+ — changes to the common +3 state.
Strong oxidising agents: Mn3+, Co3+ and Ce4+ = 3.
NCERT (2026-27 edition):
4.3.8 Chemical Reactivity and E° Values – “An examination of the Eo values for the redox couple M3+/M2+ … shows that Mn3+ and Co3+ ions are the strongest oxidising agents in aqueous solutions. The ions Ti2+, V2+ and Cr2+ are strong reducing agents and will liberate hydrogen from a dilute acid, e.g., 2 Cr2+(aq) + 2 H+(aq) → 2 Cr3+(aq) + H2(g)”
4.5.3 Oxidation States – “…Thus, the formation of CeIV is favoured by its noble gas configuration, but it is a strong oxidant reverting to the common +3 state. The Eo value for Ce4+/ Ce3+ is + 1.74 V which suggests that it can oxidise water.” … “However, Eu2+ is a strong reducing agent changing to the common +3 state.”