Half-life of a chemical reaction at a particular concentration is 50 minutes. When the concentration of the reactant is doubled, the half-life becomes 100 minutes. What is the order of reaction?
Answer & explanation
Correct answer: option 4
\(\frac{(t_{1/2})_1}{(t_{1/2})_2}\) = [\(\frac{a_2}{a_1}\)]n-1
\(\frac{50}{100}\) = [\(\frac{2}{1}\)]n-1
2-1 = 2n-1
-1 = n - 1
n = 0
Therefore, it is a zero-order reaction.