Train A takes $1\frac{4}{5}$h more than the time taken by train B to cover a distance of 360 km. If the speed of train A doubles, it will take 36 min less than the time taken by train B to travel the same distance. What is the speed (in km/h ) of train B?
Answer & explanation
Correct answer: option 4
1\(\frac{4}{5}\) hours = \(\frac{9}{5}\) hours = 108 minutes
Ratio of , Initial : Final
Speed 1 : 2
Time 2 : 1
Total time gap Between initial and final = 108 + 36 = 144 mins
( 2 - 1 )R = 144 min
1R = 144 minutes
Initial Time taken by A = 2R = 288 minutes
According to question ,
288 = 108 + B
B = 180 min = 3 hours
Speed of B = \(\frac{360}{3}\) = 120 km/h