The function f(x) = x2 - 4x; x ∈ [0, 4] attains minimum value at:
Answer & explanation
Correct answer: option 3
f(x) = x2 - 4x; x ∈ [0, 4]
f'(x) = 2x - 4, put f'(x) = 0 ⇒ 2x - 4 = 0
⇒ x = 2
Minimum value at x = 2
The function f(x) = x2 - 4x; x ∈ [0, 4] attains minimum value at:
Correct answer: option 3
f(x) = x2 - 4x; x ∈ [0, 4]
f'(x) = 2x - 4, put f'(x) = 0 ⇒ 2x - 4 = 0
⇒ x = 2
Minimum value at x = 2