Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Determinants

Question:

The rate of change of the area of a equilateral triangle with respect to its side when its side = 2 is :

Options:

$\frac{\sqrt{3}}{4}$

$\sqrt{3}$

$\frac{\sqrt{3}}{2}$

$2\sqrt{3}$

Correct Answer:

$\sqrt{3}$

Explanation:

Area of equilateral triangle with side x is A(x) = $\frac{\sqrt{3}}{4}x^2$

so rate of change of A(x) wrt x

$= A'(x) = \frac{2\sqrt{3}}{4}x$ at x = 2

$A'(2) = \frac{2\sqrt{3} × 2}{4} = \sqrt{3}$