Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

A value of $tan^{-1}\begin{Bmatrix}sin\left(cos^{-1}\sqrt{\frac{2}{3}}\right)\end{Bmatrix}$, is

Options:

$\frac{\pi}{4}$

$\frac{\pi}{2}$

$\frac{\pi}{3}$

$\frac{\pi}{6}$

Correct Answer:

$\frac{\pi}{6}$

Explanation:

$tan^{-1}\begin{Bmatrix}sin\left(cos^{-1}\sqrt{\frac{2}{3}}\right)\end{Bmatrix}$

$=tan^{-1}\begin{Bmatrix}sin\left(sin^{-1}\sqrt{\frac{1}{3}}\right)\end{Bmatrix}=tan^{-1}\frac{1}{\sqrt{3}}=\frac{\pi}{6}$