The power factor of an ac circuit having resistance R and inductance L connected in series is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{R}{(R^2+w^2L^2)^{\frac{1}{2}}}$
Power factor of an AC circuit with resistance R and inductance L connected in series is -
$PF=\frac{R}{Z}$
R = Resistance
Z = Impedance
$PF=\frac{R}{\sqrt{R^2+(X_L)^2}}$
$=\frac{R}{\sqrt{R^2+w^2L^2}}$ $[X_L=wL]$