The power factor of an ac circuit having resistance R and inductance L connected in series is:

$\frac{R}{(R^2+w^2L^2)^{\frac{1}{2}}}$

The correct answer is Option (2) → $\frac{R}{(R^2+w^2L^2)^{\frac{1}{2}}}$

Power factor of an AC circuit with resistance R and inductance L connected in series is -

$PF=\frac{R}{Z}$

R = Resistance

Z = Impedance

$PF=\frac{R}{\sqrt{R^2+(X_L)^2}}$

$=\frac{R}{\sqrt{R^2+w^2L^2}}$   $[X_L=wL]$