Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

The power factor of an ac circuit having resistance R and inductance L connected in series is:

Options:

$\frac{R}{wL}$

$\frac{R}{(R^2+w^2L^2)^{\frac{1}{2}}}$

$\frac{wL}{R}$

$\frac{R}{(R^2-w^2L^2)^{\frac{1}{2}}}$

Correct Answer:

$\frac{R}{(R^2+w^2L^2)^{\frac{1}{2}}}$

Explanation:

The correct answer is Option (2) → $\frac{R}{(R^2+w^2L^2)^{\frac{1}{2}}}$