Four equal resistors are connected  in series across a source of emf. Together they dissipate 5 W of power. If the same four equal resistors are connected in parallel across the same source of emf then the total power dissipated will be

40 W  $\frac{5}{32}$ W 80 W $\frac{5}{16}$W

80 W

In Series $P = \frac{V^2}{4R}$ In Parallel $P' = \frac{4V^2}{R} $ $ \frac{P'}{P} = 16 $ $ \Rightarrow P'= 16P = 80W$