Practicing Success
Practicing Success
CUET Preparation Today
| The area of the region between the circles \(x^2+y^2=4\) and \((x-2)^2+y^2=4\) is |
\(\frac{8\pi}{3}-2\sqrt{3}\) \(\frac{8\pi}{3}+2\sqrt{3}\) \(\frac{8\pi}{3}-\sqrt{3}\) \(\frac{8\pi}{3}+\sqrt{3}\) |
| \(\frac{8\pi}{3}-2\sqrt{3}\) |
| Use integration |
