The area of the region between the circles \(x^2+y^2=4\) and \((x-2)^2+y^2=4\) is1\(\frac{8\pi}{3}-2\sqrt{3}\)2\(\frac{8\pi}{3}+2\sqrt{3}\)3\(\frac{8\pi}{3}-\sqrt{3}\)4\(\frac{8\pi}{3}+\sqrt{3}\)Answer & explanation+Correct answer: option 1Use integration
