If one side of a square is increased by 40%, by what percentage another side is reduced so that its area remains same?
Answer & explanation
Correct answer: option 1
Area = Side1 × Side2
*(When area is constant, then the relation b/w sides are inversely proportional)
Side1 : 5 : 7
Side2 : 7 : 5
Side2 should be reduced by = 7 - 5 = 2
So, Reduce percent = \(\frac{2}{7}\) × 100 = 28\(\frac{4}{7}\)%