If one side of a square is increased by 40%, by what percentage another side is reduced so that its area remains same?

28\(\frac{4}{7}\)% 25\(\frac{4}{7}\)% 18\(\frac{4}{7}\)% 20\(\frac{4}{7}\)%

28\(\frac{4}{7}\)%

Area = Side1 × Side2 *(When area is constant, then the relation b/w sides are inversely proportional) Side1  :  5  :   7 Side2  :  7  :   5 Side2 should be reduced by = 7 - 5 = 2 So, Reduce percent = \(\frac{2}{7}\) × 100 = 28\(\frac{4}{7}\)%