Practicing Success
An n – p – n transistor circuit has $α$ = 0.985. If $I_c = 2mA$, then value of $I_b$ is - |
0.03 mA 0.003 mA 0.66 mA 0.015 mA |
0.03 mA |
$α=\frac{I_c}{I_e}=\frac{I_c}{I_c+I_b}=0.985$ $I_c = 0.985 (I_c + I_b)$ $I_c = 0.985\, I_c + 0.985\, I_b$ $0.985 I_b = 0.015 I_c = 0.015 × 2 mA$ $I_b = \frac{0.015 ×2}{0.985}= 0.03 mA$ $I_b≈0.03mA$ |