Study of radioactive decay of unstable nuclei resulting in emission of a particle lead us to four different observations listed below: (A) no change in atomic number and mass number. Arrange the particles emitted in the above four cases in correct sequence. |
alpha particle, positron, electron, photon. alpha particle, electron, positron, photon. photon, positron, electron, alpha particle. alpha particle, positron, photon, electron. |
photon, positron, electron, alpha particle. |
The correct answer is Option (3) → photon, positron, electron, alpha particle. (A) This corresponds to ($γ$) decay, where only energy is emitted as photons, and there is no change in the nucleus. (B) This corresponds to beta-plus $(β^+)$ decay or positron emission, where a proton is converted into neutron, and the atomic number decreases by 1. (C) This corresponds to beta-minus $(β^-)$ decay, where a neutron is converted into proton and the atomic number increases 1. (D) This corresponds to Alpha ($α$)-decay, where a helium nucleus is emitted. |