Practicing Success
A and B can complete a certain work in 27 days and 45 days, respectively. They worked together for 10 days. C alone completed the remaining work in 5 days, A and C together can complete \(\frac{7}{15}\)th of the same work in: |
8 days 9 days 4 days 4.5 days |
4.5 days |
Efficiency of A + B = 5 + 3 = 8 Work done in 10 days = (efficiency of A + B) x No. of days = 8 x 10 = 80 Remaining work = 135 - 80 = 55 This work is done by C alone in 5 days, Then efficiency of C = \(\frac{work\; done}{no.\; of\; days}\) = \(\frac{55}{5}\) = 11 Efficiency of A + C = 3 + 11 = 14 Time taken by A and C to complete \(\frac{7}{15}\)th of the work = \(\frac{Total \; work}{efficiency}\) x \(\frac{7}{15}\) = \(\frac{135}{14}\) x \(\frac{7}{15}\) = 4.5 days
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