Practicing Success
Practicing Success
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If $f(x) = \sin^2 x$ and the composite function $g(f(x))= |\sin x|$, then g(x) is equal to |
$\sqrt{x-1}$ $\sqrt{x}$ $\sqrt{x+1}$ $-\sqrt{x}$ |
$\sqrt{x}$ |
The correct answer is Option (2) → $\sqrt{x}$ We have, $f(x) = \sin^2 x$ and $g(f(x))= |\sin x|$ Now, $g(f(x))= |\sin x|$ $⇒g(f(x))=\sqrt{\sin^2 x}⇒g(\sin^2 x)=\sqrt{\sin^2 x}$ $∴g(x)=\sqrt{x}$ |
