A regular hexagon of side 12 cm has a charge of \( 6\,\mu\mathrm{C} \) at each of its vertices. What will be the potential at the centre of the hexagon?
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 2.7\times10^{6}\,\mathrm{V} \)
The potential is a scalar, so the potential at the centre is the sum of the potentials of the six charges. In a regular hexagon the distance from the centre to each vertex equals the side, \( a = 12\,\mathrm{cm} \).
\( \displaystyle V = 6\,\frac{kq}{a} \)
\( k = 9\times10^{9}\,\mathrm{N\,m^{2}\,C^{-2}} \)
\( q = 6\times10^{-6}\,\mathrm{C} \)
\( a = 0.12\,\mathrm{m} \)
\( \displaystyle V = \frac{6\times9\times10^{9}\times6\times10^{-6}}{0.12} = 2.7\times10^{6}\,\mathrm{V} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
